백준 10845번 - 큐

n,*l=open(0)
a=[]

for i in l:
  if (cmd:=(q:=i.split())[0]) == 'push': a.append(q[1])
  elif cmd == 'pop': print(a.pop(0) if a else -1)
  elif cmd == 'size': print(len(a))
  elif cmd == 'empty': print(0 if a else 1)
  elif cmd == 'front': print(a[0] if a else -1)
  elif cmd == 'back': print(a[-1] if a else -1)

s=[];p=print
for o in [*open(0)][1:]:
 match o[1]:
  case "u":s.append(o.split()[1])
  case "o":p(s.pop(0)if s else-1)
  case "i":p(len(s))
  case "m":p(0 if s else 1)
  case "r":p(s[0]if s else-1)
  case "a":p(s[-1]if s else-1)